Monday, July 5, 2021

Beyond pythagoras

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The numbers , 4 and 5 satisfy this condition


+ 4 = 5


because = x =


4 = 4 x 4 = 16


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5 = 5 x 5 = 5


and so + 4 = + 16 = 5 = 5


The numbers 5, 1, 1 and 7, 4, 5 also work for this theorem


5 + 1 = 1


because 5 = 5 x 5 = 5


1 = 1 x 1 = 144


1 = 1 x 1 = 16


and so 5 + 1 = 5 + 144 = 16 = 1


7 + 4 = 5


because 7 = 7 x 7 = 4


4 = 4 x 4 = 576


5 = 5 x 5 = 65


and so 7 + 4 = 4 + 576 = 65 = 5 essaybank.co.uk


, 4, 5


Perimeter = + 4 + 5 = 1


Area = ½ x x 4 = 6


5, 1, 1


Perimeter = 5 + 1 + 1 = 0


Area = ½ x 5 x 1 = 0


7, 4, 5


Perimeter = 7 + 4 + 5 = 56


Area = ½ x 7 x 4 = 84


From the first three terms I have noticed the following -


?a? increases by + each term


?a? is equal to the term number times then add 1


the last digit of ?b? is in a pattern 4, , 4


the last digit of ?c? is in a pattern 5, , 5


the square root of (?b? + ?c?) = ?a?


?c? is always +1 to ?b?


?b? increases by +4 each term


(?a? x ?n?) + n = ?b?


Now I will complete the square on ?4n + 6n + ? to see what the solution to this is.


4n + 6n +


4(n +) - +


4(n +) - 7


4(n +) = 7


(n +) = 1.75


n + = 1.875656


n + = -1.875656


n = -1.6771444


n = -4.875656


Arithmatic Progression


I would like to know whether or not the Pythagorean triple ,4,5 is the basis of all triples just some of them.


To find this out I have been to the library and looked at some A-level textbooks and learnt ?Arithmatic Progression?


, 4, 5 is a Pythagorean triple


The pattern is plus one


If a = and d = difference (which is +1) then


= a


4 = a + d


5 = a +d


MQ8FnH from MQ8FnH essay MQ8FnH bank MQ8FnH co MQ8FnH uk


a, a +d, a + d


Therefore if you incorporate this into Pythagoras theorem


a + (a + d) = (a + d)


a + (a + d)(a + d) = (a + d)


a + a + ad + ad + d = (a + d)


a + ad + d = (a + d)


a + ad + d = (a + d)(a + d)


a + ad + d = a + ad + ad + 4d


a + ad + d = 4d + a + 4ad


wwcb cbw escbcbs aycb cbba ncb kccb cbuk!


If you equate these equations to 0 you get


a - d - ad = 0


Change a to x


x - d - dx = 0


Factorise this equation to get


(x + d)(x - d)


Therefore


x = -d


x = d


x = -d is impossible as you cannot have a negative dimension


a, a+d, a + d


Is the same as


d, 4d, 5d


This tells us that the only Pythagorean triples are , 4, 5 or multiples of , 4, 5 e.g. 6, 8, 10 or 1, 16, 0 etc.


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